Previous Year Papers / JEE Main / 2022

JEE Main 2022 Question Paper & Answers

The official JEE Main 2022 question paper, with the official answer key. Attempt as a real timed exam (with negative marking) or switch to practice mode for instant per-question answers and explanations.

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Official PYQ

JEE Main 2022 - June 24 Morning Shift

180 Mins 300 Marks
75Questions
300Max Marks

Sample questions from JEE Main 2022 - June 24 Morning Shift

1The bulk modulus of a liquid is 3×1093\times10^9 Nm−2^{-2}. The pressure required to reduce the volume of the liquid by 2% is:
  • A) 3×1093\times10^9 Nm−2^{-2}
  • B) 9×1099\times10^9 Nm−2^{-2}
  • C) 6×1076\times10^7 Nm−2^{-2}
  • D) 12×10812\times10^8 Nm−2^{-2}
Answer: C
2Given below are two statements, one labelled as Assertion (A) and the other labelled as Reason (R).
Assertion (A): In a uniform magnetic field, speed and energy remain the same for a moving charged particle.
Reason (R): A moving charged particle experiences a magnetic force perpendicular to its direction of motion.
Choose the correct answer:
  • A) Both (A) and (R) are true and (R) is the correct explanation of (A)
  • B) Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  • C) (A) is true but (R) is false
  • D) (A) is false but (R) is true
Answer: A
3Two identical cells, each of emf 1.5 V, are connected in parallel across a parallel combination of two resistors, each of resistance 20 Ω20\,\Omega. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is:
  • A) 2.5 Ω2.5\,\Omega
  • B) 4 Ω4\,\Omega
  • C) 5 Ω5\,\Omega
  • D) 10 Ω10\,\Omega
Answer: C
4Identify the pair of physical quantities which have different dimensions:
  • A) Wave number and Rydberg's constant
  • B) Stress and Coefficient of elasticity
  • C) Coercivity and Magnetisation
  • D) Specific heat capacity and Latent heat
Answer: D
5A projectile is projected with a velocity of 25 m/s at an angle θ\theta with the horizontal. After tt seconds its inclination with the horizontal becomes zero. If RR represents the horizontal range of the projectile, the value of θ\theta will be (use g=10g=10 m/s2^2):
  • A) sin⁡−1(gt2R)\sin^{-1}\left(\dfrac{gt}{2R}\right)
  • B) tan⁡−1(2Rgt)\tan^{-1}\left(\dfrac{2R}{gt}\right)
  • C) tan⁡−1(gtR)\tan^{-1}\left(\dfrac{gt}{R}\right)
  • D) cot⁡−1(gt2R)\cot^{-1}\left(\dfrac{gt}{2R}\right)
Answer: D

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JEE Main 2022 Previous Year Question Paper with Answers (PYQ) | ClassScribe